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Question

Focal length and angular velocity A cylindrical container, partially filled with mercury, is rotated about its axis so that the angular speed of each cross section is ω\omega radians/second. From physics, the function ff, whose graph generates the inside surface of the mercury (see the figure), is given by

f(x)=164ω2x2+k,f(x)=\frac{1}{64} \omega^2 x^2+k,

where kk is a constant. Determine the angular speed ω\omega that will result in a focal length of 22 feet.

Solution

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Answered 2 years ago
Answered 2 years ago
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The given equation f(x)=164ω2x2+kf(x) = \dfrac{1}{64}\omega^2x^2+k is similar to the standard form of the parabola f(x)=ax2+bx+cf(x) =ax^2 + bx +c where the focal length pp is equal to 14a\dfrac{1}{4a}

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