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Question

Following are forecasts of worldwide annual cell phone handset sales:

Year x357Sales y (millions)500600800\begin{matrix} \text{Year x} & \text{3} & \text{5} & \text{7}\\ \text{Sales y (millions)} & \text{500} & \text{600} & \text{800}\\ \end{matrix}

(x=3 represents 2003). Complete the following table and obtain the associated regression line. (Round coefficients to 2 decimal places.)

xyxyx2350056007800Totals\begin{matrix} & \text{} & \text{x} & \text{y} & \text{xy} & \text{}{x^{2}}\\ & \text{} & \text{3} & \text{500} & \text{} & \text{}\\ & \text{} & \text{5} & \text{600} & \text{} & \text{}\\ & \text{} & \text{7} & \text{800} & \text{} & \text{}\\ \text{Totals} & \text{} & \text{} & \text{} & \text{}\\ \end{matrix}

Use your regression equation to project the 2008 sales.

Solution

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Answered 2 years ago
Answered 2 years ago
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Given the set of points

(x1,y1),(x2,y2),,(xn,yn)(\mathrm{x}_{1},y_{1}), (x_{2},y_{2}), \ldots, (x_{n},y_{n})

The regression line (least squares line, best-fit line):

y=mx+b,y=mx+b,

where mm and bb are computed as follows.

m=n(xy)(x)(y)n(x2)(x)2b=ym(x)nm=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^{2})-(\sum x)^{2}}\qquad b=\frac{\sum y-m(\sum x)}{n}

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