Question

For a simple random sample of 15 items from a population that is approximately normally distributed, xˉ=82.0\bar{x}=82.0 and s=20.5s=20.5. At the 0.050.05 level of significance, test H0:μ90.0H_0: \mu \geq 90.0 versus H1:μ<90.0H_1: \mu<90.0.

Solution

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Answered 12 months ago
Answered 12 months ago
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For this exercise, apply the tt-test formula to describe the sampling distribution of the given mean because the population standard deviation is unknown and the value of sample standard deviation (ss) is given. Use ss to estimate σ\sigma. The tt-test formula for a sample mean:

t=xμ0s/n,\begin{aligned} t = \dfrac{\overline{x} - \mu_0}{s / \sqrt{n}}, \end{aligned}

where x\overline{x} represents the sample mean, μ0\mu_0 represents the hypothesized population mean, ss represents the sample standard deviation and nn represents the sample size.

It is given that the sample size is n=15n=15, the sample standard deviation is s=20.5s = 20.5, the sample mean is x=82.0\overline{x} = 82.0, and the level of significance is α=0.05\alpha = 0.05.

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