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Question

For following fitted trend, make a prediction for period tt = 17:

yty_t = 501 + 18.2tt - 7.1t2{t}^2

Solution

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Answered 1 year ago
Answered 1 year ago
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We are given the fitted quadratic trend

yt=501+18.2t7.1t2y_t=501+18.2t-7.1t^2

therefore the forecast for period t=17t=17 is

y17=501+18.2(17)7.1(17)2=1241.5y_{17}=501+18.2(17)-7.1(17)^2=-1241.5

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