Question

For following fitted trend, make a prediction for period $t$ = 17:

$y_t$ = 501 + 18.2$t$ - 7.1${t}^2$

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 2We are given the fitted quadratic trend

$y_t=501+18.2t-7.1t^2$

therefore the forecast for period $t=17$ is

$y_{17}=501+18.2(17)-7.1(17)^2=-1241.5$

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