Question

For [OH]=9.87×109M\left[\mathrm{OH}^{-}\right]=9.87 \times 10^{-9} \mathrm{M}, calculate the pOH\mathrm{pOH} of the solution as well as the concentration of hydrogen ion in the solution. Indicate whether the solution is acidic or basic.

Solution

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Answered 1 year ago
Answered 1 year ago
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We can calculate pOHpOH of our solution using this expression:

pOH=log([OH])pOH=-log(\text{[OH$^-$]})

pOH=log(9.87×109)=8.01pOH=-log(9.87 \times 10^{-9})=8.01

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