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For saving energy, bicycling and walking are far more efficient means of transportation than is travel by automobile. For example, when riding at 10.0 mi/h, a cyclist uses food energy at a rate of about 400 kcal/h above what he would use if merely sitting still. (In exercise physiology, power is often measured in kcal/h rather than in watts. Here 1 kcal = 1 nutritionist’s Calorie = 4 186 J.) Walking at 3.00 mi/h requires about 220 kcal/h. It is interesting to compare these values with the energy consumption required for travel by car. Gasoline yields about 1.30×1081.30 \times 108 J/gal. Find the fuel economy in equivalent miles per gallon for a person (a) walking and (b) bicycling.

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Answered 2 years ago
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a)

Lets convert the power of the person walking from kcal/h to J/h:

Pw=220kcalh4186J1kcal=920920Jh\begin{align*} P_w&=220\frac{\,\text{kcal}}{\,\text{h}}\cdot \frac{4186\,\text{J}}{1\,\text{kcal}}\\ &=920920\frac{\,\text{J}}{\,\text{h}} \end{align*}

Next, lets convert the J/h into gal/h:

Pw=920920Jh1gal1.3108J=7.084103galh\begin{align*} P_w&=920920\frac{\,\text{J}}{\,\text{h}} \cdot \frac{1\,\text{gal}}{1.3\cdot 10^{8}\,\text{J}}\\ &=7.084\cdot 10^{-3}\frac{\,\text{gal}}{\,\text{h}} \end{align*}

Person walks 3 miles in one hour, so he does :

Nw=3mih7.084103galh=423.49migal\begin{align*} N_w&=\frac{3\frac{\,\text{mi}}{\,\text{h}}}{7.084\cdot 10^{-3}\frac{\,\text{gal}}{\,\text{h}}}\\ &=\boxed{423.49\frac{\,\text{mi}}{\,\text{gal}}} \end{align*}

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