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Question

For the following exercise,

Evaluate each root.

Evaluate the cube root of zz when z=32cis(2π3)z=32 \operatorname{cis}\left(\frac{2 \pi}{3}\right).

Solution

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Answered 1 year ago
Answered 1 year ago
Step 1
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Since

cisθ=cosθ+isinθ\mathrm{cis} \theta=\cos \theta+i\sin \theta

we can rewrite the expresion:

z=32[cos(2π3)+isin(2π3)]z=32\left[\cos\left(\dfrac{2\pi}{3}\right)+i\sin\left(\dfrac{2\pi}{3}\right)\right]

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