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Question

For the following problem, find the area.

The parallelogram determined by c=4i+4ȷ7k\vec{c}=4 \vec{i}+4 \vec{\jmath}-7 \vec{k} and d=2i+5j14k\vec{d}=-2 \vec{i}+5 \vec{j}-14 \vec{k}

Solution

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c=4i^+4j^7k^\overline{c} = 4\widehat{i}+4\widehat{j}-7\widehat{k}

d=2i^+5j^14k^\overline{d} = -2\widehat{i}+5\widehat{j}-14\widehat{k}

Given points\text{\textcolor{#c34632}{Given points}}

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