## Related questions with answers

Question

For the following problem, find the point where the given line intersects the given plane.

Line: $\vec{r}=\left(4+\frac{1}{3} d\right) \vec{t}+\left(1+\frac{2}{3} d\right)\vec {j}+\left(7+\frac{2}{3} d\right) \vec{k}.$

Plane: $x+4 y-3 z=35$

Solution

VerifiedStep 1

1 of 5$\overline{r}=(4+\dfrac{1}{3}d)\widehat{i}+(1+\dfrac{2}{3}d)\widehat{j}+(7+\dfrac{2}{3}d)\widehat{k}$

$x+4y-3z=35$

$\text{\textcolor{#c34632}{Given}}$

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