Below are two solution procedures for solving
sin2θ−21sinθ=0 for 0∘≤θ<360∘.
Which is incorrect? Explain the error. A.
sin2θ−21sinθ=0sinθ(sinθ−21)=0sinθ=0 or sinθ=21θ=0∘ or 180∘ or θ=30∘ or 150∘
B.
sin2θ−21sinθsin2θsinθθ=0=21sinθ=21=30∘ or 150∘