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Question

For the mineral torbernite, Cu(UO2)2(PO4)28H2O\mathrm{Cu}\left(\mathrm{UO}_2\right)_2\left(\mathrm{PO}_4\right)_2 \cdot 8 \mathrm{H}_2 \mathrm{O}, determine the mass required to contain 1.00 gP1.00 \mathrm{~g} \mathrm{P}

Solution

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Answered 2 years ago
Answered 2 years ago

The mass required to contain 1.00 g P

Given:

Molar mass of compound = 933.66 g/mol

Mass of torbernite required to contain 1.0 g P

(1) Solve for the mass requires to contain 1.00 g P as shown below:

Mass required = 1.0 g P x 1 mol P30.9738 g P\dfrac{\text{1 mol P}}{\text{30.9738 g P}} x 1 mol torbernite2 mol P\dfrac{\text{1 mol torbernite}}{\text{2 mol P}} x 933.66 g torbernite1 mol torbernite\dfrac{\text{933.66 g torbernite}}{\text{1 mol torbernite}}

Mass required = 15.1 g torbernite / g P

Thus, the mass required to contain 1.00 g P is 15.1 gm.\textbf{Thus, the mass required to contain 1.00 g P is 15.1 gm.}

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