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For the mineral torbernite, Cu(UO2)2(PO4)28H2O\mathrm{Cu}\left(\mathrm{UO}_2\right)_2\left(\mathrm{PO}_4\right)_2 \cdot 8 \mathrm{H}_2 \mathrm{O}, determine the ratio, by mass, of Cu\mathrm{Cu} to P\mathrm{P}

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Answered 2 years ago
Answered 2 years ago

The ratio, by mass, of Cu to P

(1) Solve for the ratio and take note that one mole of compound contains one mole Cu and two moles P as shown below:

Mass of CuMass of P\dfrac{\text{Mass of Cu}}{\text{Mass of P}} =  1 mol Cu x 63.546 g Cu/mol Cu2 mol P x 30.9738 g P/mol P\dfrac{\text{ 1 mol Cu x 63.546 g Cu/mol Cu}}{\text{2 mol P x 30.9738 g P/mol P}}

Mass of CuMass of P\dfrac{\text{Mass of Cu}}{\text{Mass of P}} = 1.0261.000\dfrac{1.026}{1.000}

Thus, the ratio, by mass of Cu to P is 1.026/1.000.\textbf{Thus, the ratio, by mass of Cu to P is 1.026/1.000.}

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