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# For the mineral torbernite, $\mathrm{Cu}\left(\mathrm{UO}_2\right)_2\left(\mathrm{PO}_4\right)_2 \cdot 8 \mathrm{H}_2 \mathrm{O}$, determine the ratio, by mass, of $\mathrm{Cu}$ to $\mathrm{P}$

Solution

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The ratio, by mass, of Cu to P

(1) Solve for the ratio and take note that one mole of compound contains one mole Cu and two moles P as shown below:

$\dfrac{\text{Mass of Cu}}{\text{Mass of P}}$ = $\dfrac{\text{ 1 mol Cu x 63.546 g Cu/mol Cu}}{\text{2 mol P x 30.9738 g P/mol P}}$

$\dfrac{\text{Mass of Cu}}{\text{Mass of P}}$ = $\dfrac{1.026}{1.000}$

$\textbf{Thus, the ratio, by mass of Cu to P is 1.026/1.000.}$

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