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f(x)=sinx,g(x)=cosx,h(x)=2x,f(x)=\sin x, g(x)=\cos x, h(x)=2 x, and p(x)=x2.p(x)=\frac{x}{2}. Find the value of each of the following: (fg)(60)(f-g)\left(60^{\circ}\right)


Answered 1 year ago
Answered 1 year ago
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In order to find the value of the given function, let us note that f(60°)=sin60°f(60\degree)=\sin60\degree while g(60°)=cos60°g(60\degree)=\cos60\degree where we need to determine first its exact value by using the points on the unit circle that corresponds to the angle, hence we now have:

sin60°=32 and cos60°=12 .\sin 60\degree=\frac{\sqrt3}{2} \text{ and } \cos60\degree=\frac{1}{2}~.

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