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Gaseous E10 fuel is 10 percent ethanol (C2H6O)\left(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\right) and 90 percent octane (C8H18)\left(\mathrm{C}_{8} \mathrm{H}_{18}\right) on a kmol basis. This fuel is burned with 110 percent theoretical air. During the combustion process, 90 percent of the carbon in the fuel is converted to CO2\mathrm{CO}_{2} and 10 percent is converted to CO. Determine (a) the balanced combustion equation, (b) the dew-point temperature of the products, in C^{\circ} \mathrm{C}, for a product pressure of 100 kPa, (c) the heat transfer for the process, in kJ, after 2.5 kg of fuel are burned and the reactants and products are at 25C25^{\circ} \mathrm{C} with the water in the products remaining a gas, and (d) the relative humidity of atmospheric air for the case where the atmospheric air is at 25C25^{\circ} \mathrm{C} and 100 kPa and the products are found to contain 9.57 kmol of water vapor per kmol of fuel burned.

hˉf,kJ/kmolM, kg/kmolC3H18(g)-208,450144C2H6O(g)-235,310 46CO2-393,52044CO-110,53028H2O(g)-241,820 18H2O(l)-285,83018O232N228\begin{matrix} \text{} & \text{}{\bar{h}_{f}^{\circ}, \mathrm{kJ} / \mathrm{kmol}} & \text{M, kg/kmol}\\ \text{}{\mathrm{C}_{3} \mathrm{H}_{18}(g)} & \text{-208,450} & \text{144}\\ \text{}{\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}(g)} & \text{-235,310 } & \text{46}\\ \text{}{\mathrm{CO}_{2}} & \text{-393,520} & \text{44}\\ \text{CO} & \text{-110,530} & \text{28}\\ \text{}{\mathrm{H}_{2} \mathrm{O}(g)} & \text{-241,820 } & \text{18}\\ \text{}{\mathrm{H}_{2} \mathrm{O}(\mathrm{l})} & \text{-285,830} & \text{18}\\ \text{}{\mathrm{O}_{2}} & \text{} & \text{32}\\ \text{}{\mathrm{N}_{2}} & \text{} & \text{28}\\ \end{matrix}

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