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Give a structure for an optically inactive compound AA (C6H10O4)\left(\mathrm{C}_6 \mathrm{H}_{10} \mathrm{O}_4\right), that can be resolved into enantiomers and has the following NMR spectra: 13C{ }^{13} \mathrm{C} NMR: δ13.5,δ41.2,δ177.9\delta 13.5, \delta 41.2, \delta 177.9 proton NMR: δ1.13(6H, d,J=7 Hz);δ2.65\delta 1.13(6 H, \mathrm{~d}, J=7 \mathrm{~Hz}) ; \delta 2.65 ( 2H2 H, quintet, J=7 Hz);δ9.9(2HJ=7 \mathrm{~Hz}) ; \delta 9.9\left(2 \mathrm{H}\right., broad s, disappears after D2O\mathrm{D}_2 \mathrm{O} shake)

Give the structure of an isomer of compound A that has a different melting point than A and NMR spectra that are almost identical to those of A.

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Answered 2 years ago
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(a)

We are asked to give a structure for compound A based on the given pieces of information: \\[1.2em]

  • the molecular formula C6_6H10_{10}O4_4, \\[1.2em]
  • compound is optically inactive and can be resolved into enantiomers, \\[1.2em]
  • data from the 13^{13}C and 1^{1}H NMR spectra.

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