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Question

Given the three-step "blast furnace" process that converts iron ore, Fe2O3\mathrm{Fe}_2 \mathrm{O}_3, into molten "pig iron":

3Fe2O3(l)+CO(g)2Fe3O4(l)+CO2(g)Fe3O4(l)+CO(g)3FeO(l)+CO2(g)FeO(l)+CO(g)Fe(l)+CO2(g)\begin{aligned} & 3 \mathrm{Fe}_2 \mathrm{O}_3(l)+\mathrm{CO}(g) \rightarrow 2 \mathrm{Fe}_3 \mathrm{O}_4(l)+\mathrm{CO}_2(g) \\ & \mathrm{Fe}_3 \mathrm{O}_4(l)+\mathrm{CO}(g) \rightarrow 3 \mathrm{FeO}(l)+\mathrm{CO}_2(g) \\ & \mathrm{FeO}(l)+\mathrm{CO}(g) \rightarrow \mathrm{Fe}(l)+\mathrm{CO}_2(g) \\ & \end{aligned}

What mass of Fe2O3\mathrm{Fe}_2 \mathrm{O}_3 produces 1.001.00 metric ton (1000 kg) of iron?

a. 175 kg175 \mathrm{~kg}

b. 699 kg699 \mathrm{~kg}

c. 715 kg715 \mathrm{~kg}

d. 1430 kg1430 \mathrm{~kg}

e. 2860 kg2860 \mathrm{~kg}

Solution

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The goal of this exercise is to determine the mass of iron(III) oxide needed to produce 1000 kg of iron.

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