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Question

Graph each function over a one-period interval. y=12csc(x+π2)y=1-2 \csc \left(x+\frac{\pi}{2}\right)

Solution

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We are given:

y=12csc(x+π2)y=1-2\csc \left(x+\dfrac{\pi}{2}\right)

Graph the corresponding reciprocal function as shown by the orange dashed curve:

y=12sin(x+π2)y=1-2\sin \left(x+\dfrac{\pi}{2}\right)

Note: The period of y=c+acosb(xd)y=c+a\cos b(x-d) is 2πb\frac{2\pi}{b}. Since b=1b=1, then the period is: 2π1=2π\frac{2\pi}{1}=2\pi. This is the graph of y=2sinxy=-2\sin x that is translated π2\frac{\pi}{2} to the left and translated 1 unit up.

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