Question

Graph several functions that satisfy the following differential equations. Then find and graph the particular function that satisfies the given initial condition. f'(x)=2x-5; f(0)=4

Solution

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Answered 6 months ago
Answered 6 months ago
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A function FF is and antiderivative of ff on an interval II provided F(x)=f(x)F'(x)=f(x), for all xx in II.

F(x)=2x5dx=2xdx5dx=x25x+C\begin{align*} F(x)&=\int 2x-5 \, dx \\ &= \int 2x \, dx-\int 5 \, dx\\ &=x^2-5x+C \end{align*}

We are given that F(0)=4F(0)=4, therefore

F(0)=4025(0)+C=4C=4\begin{gather*} F(0)=4\\ 0^2-5(0)+C=4\\ \boxed{C=4} \end{gather*}

Therefore,

F(x)=x25x+4\begin{gather*} F(x)=x^2-5x+4 \end{gather*}

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