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Question

Graph the circles whose equations are given. Label each circle's center and intercepts (if any) with their coordinate pairs.

x2+y24x(9/4)=0x^2+y^2-4 x-(9 / 4)=0

Solution

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Answered 2 years ago
Answered 2 years ago
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Write the given equation into the standard equation of circle. The standard equation of a circle is

(xh)2+(yk)2=a2\begin{align} (x-h)^2 + (y-k)^2 = a^2 \end{align}

Where the center is (h,k)(h,k) and the radius is aa.

To write the given equation into the standard equation (1), separate the constant on one side. After that, complete the squares for the xx and yy variables. Note that to complete a square of the expression x2+bxx^2+bx, get the value equal to (b/2)2(b/2)^2 then, add it to the expression x2+bxx^2+bx. From this, the resulting equation will be (x+b/2)2(x+b/2)^2.

x2+y24x=9/4(x4x+4)2+(y0)2=9/4+4(x2)2+(y0)2=25/4(x2)2+(y0)2=(5/2)2\begin{align*} x^2+y^2-4x & = 9/4 \\ (x-4x+4)^2 + (y-0)^2 &= 9/4 + 4\\ (x-2)^2 + (y-0)^2 &= 25/4 \\ (x-2)^2 + (y-0)^2 &= (5/2)^2 \\ \end{align*}

Thus, a=5/2a=5/2 and (h,k)=(2,0)(h,k) = (2,0).

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