## Related questions with answers

High-speed elevators function under two limitations: (1) the maximum magnitude of vertical acceleration that a typical human body can experience without discomfort is about $1.2 \mathrm{~m} / \mathrm{s}^2$, and (2) the typical maximum speed attainable is about $9.0 \mathrm{~m} / \mathrm{s}$. You board an elevator on a skyscraper's ground floor and are transported $180 \mathrm{~m}$ above the ground level in three steps: acceleration of magnitude $1.2 \mathrm{~m} / \mathrm{s}^2$ from rest to $9.0 \mathrm{~m} / \mathrm{s}$, followed by constant upward velocity of $9.0 \mathrm{~m} / \mathrm{s}$, then deceleration of magnitude $1.2 \mathrm{~m} / \mathrm{s}^2$ from $9.0 \mathrm{~m} / \mathrm{s}$ to rest. Find the change in the magnitude of the normal force, expressed as a $\%$ of your normal weight during each stage.

Solution

VerifiedIn this part we need to find the change in the magnitude of the normal force. It needs to be in written as some % of normal weight.

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