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Question

Hot water flows through a PVC (k=0.092 W/mK)(k=0.092 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}) pipe whose inner diameter is 2 cm2 \mathrm{~cm} and whose outer diameter is 2.5 cm2.5 \mathrm{~cm}. The temperature of the interior surface of this pipe is 35C35^{\circ} \mathrm{C}, and the temperature of the exterior surface is 20C20^{\circ} \mathrm{C}. The rate of heat transfer per unit of pipe length is (a) 22.8 W/m22.8 \mathrm{~W} / \mathrm{m} (b) 38.9 W/m38.9 \mathrm{~W} / \mathrm{m} (c)(c) 48.7 W/m48.7 \mathrm{~W} / \mathrm{m} (d) 63.6 W/m63.6 \mathrm{~W} / \mathrm{m} (e) 72.6 W/m72.6 \mathrm{~W} / \mathrm{m}

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Given: k=0,092WmKk=0,092 \frac{\text W}{\text m \cdot K} d1=2 cmd_1=2 \text{ cm} d2=2,5 cmd_2=2,5 \text{ cm} T1=35°CT_1=35\degree C T2=20°CT_2=20\degree C We are given inner and outer diameters and temperatures and we have to determine the rate of heat transfer per unit of pipe length.

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