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How do the average rates of change for each pair of functions compare over the given interval? f(x) = -2x², g(x) = -4x², -4 ≤ x ≤ -2

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How do the average rate of change for f(x)=2 x2f(x)=-2\ x^2 and g(x)=4 x2g(x)=-4\ x^2 over the interval 4x2-4\leq x\leq -2

f(x)=2 x2f(2)=2(2)2=24=8f(4)=2(4)2=216=32g(x)=4 x2f(2)=4(2)2=44=16f(4)=4(4)2=416=64\begin{align*} f(x) &=-2\ x^2 \\ \\ f(-2) &=-2\cdot(-2)^2=-2\cdot 4=-8 \\ \\ f(-4) &=-2\cdot(-4)^2=-2 \cdot16=-32 \\ \\ g(x) &=-4\ x^2 \\ \\ f(-2) &=-4\cdot (-2)^2=-4 \cdot4=-16 \\ \\ f(-4) &=-4\cdot (-4)^2=-4 \cdot16=-64 \end{align*}

f(x):8(32)2(4)=8+322+4=242=12f(x): \dfrac{-8-(-32)}{-2-(-4)}=\dfrac{-8+32}{-2+4}=\dfrac{24}{2}=12

g(x):16(64)2(4)=16+642+4=482=24g(x): \dfrac{-16-(-64)}{-2-(-4)}=\dfrac{-16+64}{-2+4}=\dfrac{48}{2}=24

The rate of change gg is twice the rate of change ff.

The values of function ff increase by 1212 units and the values of function gg increase by 2424 units for each unit increase in xx over the interval 4x2-4\leq x\leq -2

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