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How does f(x)=logx(2)f(x)=\log _{x}(2) compare with g(x)=log2(x)?g(x)=\log _{2}(x) ? Here is one way to find out. a. Use the equation logab=(lnb)/(lna)\log _{a} b=(\ln b) /(\ln a) to express f(x) and g(x) in terms of natural logarithms. b. Graph f and g together. Comment on the behavior of f in relation to the signs and values of g.

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Answered 1 year ago
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a) When we use given equation we can express our functions in this way:

f(x)=logx2=ln2lnxg(x)=log2x=lnxln2\begin{aligned} f(x)&=\log_x2=\frac{\ln2}{\ln x} \\ \\ g(x)&=\log_2x=\frac{\ln x}{\ln 2} \\ \end{aligned}

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