Question

How many grams of solid iron (III) chloride (FeCl3\mathrm{FeCl_{3}}) are produced when 2.00 moles of solid iron (Fe) are combined with chlorine gas (Cl2)\left(\mathrm{Cl}_{2}\right)?

  1. Analyze the Problem Known: __________ Unknown: __________ You are given the moles of the reactant, Fe, and must determine the mass of the product, FeCl3\mathrm{FeCl_{3}}, therefore, you will do a mole to mass conversion.
  2. Solve for the Unknown Write the balanced chemical equation. Identify the known and unknown substances.

Fe(s)+Cl2(g)=FeCl3(s)\mathrm{Fe}(\mathrm{s})+\square \mathrm{Cl}_{2}(\mathrm{g})=\square \mathrm{FeCl}_{3}(\mathrm{s})

List the mole ratios for this equation. Multiply the number of moles of Fe by the mole ratio.

mol Fe×mol FeCl3mol Fe=mol FeCl2\square \text{mol Fe} \times \frac{\square \mathrm{mol} \ \mathrm{FeCl_{3}}}{\square\mathrm{mol \ Fe}} = \square \mathrm{mol \ FeCl_{2}}

Multiply the moles of FeCl3\mathrm{FeCl}_{3} by the molar mass of FeCl3\mathrm{FeCl}_{3}.

molFeCl3×gFeCl31molFeCl3=gFeCl3\operatorname{mol} \mathrm{FeCl}_{3} \times \frac{\mathrm{g} \mathrm{FeCl}_{3}}{1 \mathrm{mol} \mathrm{FeCl}_{3}}=\square \mathrm{gFeCl}_{3}

  1. Evaluate the Answer The given number of moles has \square digits, so the mass of FeCl3\mathrm{FeCl}_{3} must have \square digits.

Solution

Verified
  1. Known: moles of iron = 2.00 mol Fe

Unknown: mass of solid iron (III) chloride = ? g FeCl3_{3}

  1. 2Fe(s) + 3Cl2_{2}(g) \longrightarrow 2FeCl3_{3}(s)

Mole ratio = 2 mol FeCl3_{3} / 2 mol Fe

Molar mass of FeCl3_{3} = 55.845 g + 3(35.453 g) = 162.204 g

2.00 mol Fe ×\times (2 mol FeCl3_{3} / 2 mol Fe) = 2 mol FeCl3_{3}

2 mol FeCl3_{3} x (162.204 g FeCl3_{3} / 1 mol FeCl3_{3}) = 324 g FeCl3_{3}

  1. 3 digits; 3 digits

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