Question
How many grams of solid iron (III) chloride () are produced when 2.00 moles of solid iron (Fe) are combined with chlorine gas ?
- Analyze the Problem Known: __________ Unknown: __________ You are given the moles of the reactant, Fe, and must determine the mass of the product, , therefore, you will do a mole to mass conversion.
- Solve for the Unknown Write the balanced chemical equation. Identify the known and unknown substances.
List the mole ratios for this equation. Multiply the number of moles of Fe by the mole ratio.
Multiply the moles of by the molar mass of .
- Evaluate the Answer The given number of moles has digits, so the mass of must have digits.
Solution
Verified- Known: moles of iron = 2.00 mol Fe
Unknown: mass of solid iron (III) chloride = ? g FeCl
- 2Fe(s) + 3Cl(g) 2FeCl(s)
Mole ratio = 2 mol FeCl / 2 mol Fe
Molar mass of FeCl = 55.845 g + 3(35.453 g) = 162.204 g
2.00 mol Fe (2 mol FeCl / 2 mol Fe) = 2 mol FeCl
2 mol FeCl x (162.204 g FeCl / 1 mol FeCl) = 324 g FeCl
- 3 digits; 3 digits
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