## Related questions with answers

How much energy would be required to break a helium nucleus into its constituents, two protons and two neutrons? The rest masses of a proton (including an electron), a neutron, and helium are, respectively, 1.00783 u, 1.00867 u, and 4.00260 u. (This energy difference is called the total binding energy of the $\frac{4}{2}$He nucleus.)

Solutions

Verified**Given/Constants:**

$\begin{aligned} m_{p/e}&=1.00783\text{ u} \\ m_n&=1.00867\text{ u} \\ m_{He}&=4.00260\text{ u} \\ c&=3.00\times10^{8}\text{ m/s} \end{aligned}$

Biding energy stands for increase od rest energy, that is why we add negative helium rest energy to proton,electron and neutron energy.

$\begin{align*} E&=(2(m_{p,e}+m_n)-m_{He})c^2 \\ &=(2(1,00783u + 1,00867u)-4,0026u)c^2 \\ &=\boxed{27,36 \text{ MeV}} \end{align*}$

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