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How much energy would be required to break a helium nucleus into its constituents, two protons and two neutrons? The rest masses of a proton (including an electron), a neutron, and neutral helium are, respectively, 1.00783u1.00783 \mathrm{u}, 1.00867u1.00867 \mathrm{u}, and 4.00260u4.00260 \mathrm{u}. (This energy difference is called the total binding energy of the 24He{ }_2^4 \mathrm{He} nucleus.)

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In this problem we have to show analitcally that the speed of a particle is given as

v=pc2E=pcm2c2+p2v=\frac{pc^2}{E}=\frac{pc}{\sqrt{m^2c^2+p^2}}

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