## Related questions with answers

A 50.0-kg grindstone is a solid disk 0.520 m in diameter. You press an ax down on the rim with a normal force of 160 N. The coefficient of kinetic friction between the blade and the stone is 0.60, and there is a constant friction torque of $6.50 \mathrm { N } \cdot \mathrm { m }$ between the axle of the stone and its bearings. How much time does it take the grindstone to come from 120 rev/min to rest if it is acted on by the axle friction alone?

Solution

Verified### Concepts and Principles

**Rotational Acceleration** $\alpha$: The average rotational acceleration $\alpha$ (alpha) of a rotating rigid body (sometimes called angular acceleration) is its change in rotational velocity $\Delta \omega$ during a time interval $\Delta t$ divided by that time interval:

$\begin{gather*} \alpha = \dfrac{\Delta \omega}{\Delta t} \tag{1} \end{gather*}$

The unit for rotational acceleration is $\mathrm{(rad/s)/s}=rads/^2$.

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