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Question

how should the integral in gauss's law be evaluated?

Solution

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Answered 1 year ago
Answered 1 year ago

Let's first write the Gauss's Law:

Φ=EdA=qϵ0,\begin{align*} \Phi&=\oint E\cdot dA=\dfrac{q}{\epsilon_0}, \end{align*}

where ϵ0\epsilon_0 is vacuum permittivity. We can see from this formula that electric field is integrated over a closed surface.

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