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Question

Identify whether the statement given below is true or false.

\forall real numbers a,b,c,a, b, c, \exists exactly two real numbers xx such that ax2+bx+c=0a x^2+b x+c=0. If false, find a counterexample.

Solution

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This statement is a false\text{This statement is a \textcolor{#4257b2}{false}}

$\text{This statement is not true for all real numbers aa, bb and cc}$.

$\text{For example, let a=0a=0}$

Then, given equation has only one solution:

0x2+bx+c=0bx+c=0bx=cx=cb\begin{align*}\\ 0\cdot x^{2}+b\cdot x+c=0\\ b\cdot x+c=0\\ b \cdot x=-c \tag{\text{subtract $c$ from both sides}}\\ x=-\dfrac{c}{b} \tag{\text{divide both sides by $b$}}\\ \end{align*}

$\text{So, if a=0a=0, then, given equation}$ ax2+bx+c=0a\cdot x^{2}+b\cdot x+c=0 $\text{has only one solution x=cbx=-\dfrac{c}{b}}$

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