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If 25.5025.50 mol of helium gas is at 10°C10\degree\mathrm{C} and a gauge pressure of 0.3500.350 atm, calculate (a) the volume of the helium gas under these conditions, and (b) the temperature if the gas is compressed to precisely half the volume at a gauge pressure of 1.001.00 atm.

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Given/Constants

n=25.50 molP=0.350 atmR=8.315 J/mol-KT=10C=283.15 K\begin{aligned} n&=25.50\text{ mol} \\ P&=0.350\text{ atm} \\ R&=8.315\text{ J/mol-K} \\ T&=10^\circ\text{C}=283.15\text{ K} \end{aligned}

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