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Question

If a particle’s position is given by $x = 4- 12t + 3t^2$ (where t is in seconds and x is in meters), what is it moving in the positive or negative direction of x just then?

Solution

VerifiedAnswered 6 months ago

Answered 6 months ago

**Part b:**

To know whether it is moving in the positive or the negative x-direction, we calculate its velocity at that time and see whether it has a negative or a positive value.

Since it has a negative value, so it is moving in the negative x-direction.

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