Related questions with answers
Question
If
are disjoint nonempty compact sets, show that there exist
such that
Solution
VerifiedStep 1
1 of 2Let and be disjoint nonempty compact sets.
is compact. Let be a sequence such that for every . Because of Bolzano-Weierstrass Theorem 3.4.8. we know that there exists a subsequence and since is closed it follows that the limit of is in .
In other words, every sequence in has a subsequence that converges to a point that is in . Now, we know that is bounded wich means that it has an infimum and supremum.
Let and and lets observe their difference:
As and are bounded it follows that is also bounded a therefore has infimum. We have:
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