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# If$\overrightarrow{\mathrm{AB}}=\left( \begin{array}{c}{-1} \\ {3} \\ {2}\end{array}\right), \overrightarrow{\mathrm{AC}}=\left( \begin{array}{c}{2} \\ {-1} \\ {4}\end{array}\right)$, and$\overrightarrow{\mathrm{BD}}=\left( \begin{array}{c}{0} \\ {2} \\ {-3}\end{array}\right)$, find: $\overrightarrow{\mathrm{CD}}$

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Step 1
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Let:

$\overrightarrow{\mathrm{BD}}=\left(\begin{array}{c}0 \\ 2 \\ -3\end{array}\right) \tag{1}$

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