Question

If the bacteria E. coli synthesize DNA at a rate of 100,000 nucleotides per min and it takes 30 min to replicate the DNA, how many base pairs are in an E. coli chromosome?

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Given that E. coli\textit{E. coli} synthesize DNA at a rate of 100,000 nucleotides per min and it takes 30 min to replicate the DNA, we simply multiply them and divide it by 2 to get the number of base pairs.

100,000nucleotidesmin30 min 12=1500000 or 1.5Mb\begin{align*} 100,000 \dfrac{\text{nucleotides}}{\text{min}} \cdot 30 \text{ min } \cdot \dfrac{1}{2}=1500000 \text{ or 1.5Mb} \end{align*}

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