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If the collector supply voltage is doubled, what happens to the load line?

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Answered 2 years ago
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If VCCV_CC increases, both characteristic curve points IC(sat)I_{C(sat)} and VCE(cutoff)V_{CE(cutoff)} are affected in the same manner (remember that IC(sat)=VCC/RCI_{C(sat)}=V_{CC}/R_C and VCE(cutoff)=VCCV_{CE(cutoff)}=V_{CC}), hence the load line keeps the slope constant but the intersection points with the axis (IC(sat)I_{C(sat)} and VCE(cutoff)V_{CE(cutoff)}) increase their values. In this case, with VCC=10 VV_{CC}=10\ \mathrm{V}, then:

IC(sat)=VCCRC=10470=21.28 mA\begin{align*} I_{C(sat)}&=\frac{V_{CC}}{R_C}\\ &=\frac{10}{470}\\ &=21.28\ \mathrm{mA} \end{align*}

and VCE(cutoff)=VCC=10 VV_{CE(cutoff)}=V_{CC}=10\ \mathrm{V}, both parameters were doubled too.

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