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Question

If the kinetic energy of a particle is doubled, by what factor has its speed increased?

Solution

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Answered 1 year ago
Answered 1 year ago
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As we know, the kinetic energy of a particle can be written as:

KE=mv22(1)KE=\dfrac{mv^2}{2} \tag1

Since we need to determine by which factor the velocity of the particle increases if the kinetic energy is doubled, we need to rearrange equation (1).

2KE=mv2v2=2KEmv=2KEm\begin{align*} 2 KE &= m v^2 \\ v^2 &=\dfrac{2 KE}{m}\\ \Rightarrow v &=\sqrt{\dfrac{2 KE}{m}}\\ \end{align*}

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