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If you double the temperature of a blackbody, by what factor will the total energy radiated per second per square meter increase ?

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Answered 2 years ago
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In the Problem, the Temperature is double, i.e.

Ts=2TiT_s=2T_i

Es=σTs4=σ(2Ti)4=σ24(Ti)4=16σ(Ti)4=16EiE_s = \sigma T_s^4=\sigma (2T_i)^4=\sigma 2^4(T_i)^4=16 \sigma (T_i)^4=16 E_i

Using Stefan-Boltzmann Law\text{\textcolor{#4257b2}{Using Stefan-Boltzmann Law}}

E=σT4\boxed{E = \sigma T^4}

where: E is the energy emitted per unit area, or intensity,

σ is a constant, and

T is the temperature (measured in Kelvins).

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