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Question

In a balanced three-phase wye–wye system, the source is an abc-sequence set of voltages and $\mathbf{V}_{a n}=153.53 \angle 30.13^{\circ} \mathrm{V} \mathrm{rms}$. The load voltage on the a phase is $110.65 \angle 29.03^{\circ} \mathrm{V} \mathrm{rms}$ rms and the load impedance is $16+j 20 \Omega$. Find the line impedance.

Solution

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1 of 3We can represent our circuit as follows:

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