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Question

In a game of poker, five players are each dealt 5 cards from a 52-card deck. How many ways are there to deal the cards?

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Answered 2 years ago
Answered 2 years ago
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Given:

n1=n2=n3=n4=n5=5n_1=n_2=n_3=n_4=n_5=5

n=52n=52

Definition multinomial coefficients: The number of ways in which ways nn objects can be grouped into rr classes with nin_i the size of the iith class are

(nn1n2....nr)=n!n1!n2!...nr!\left(\begin{matrix}n \\ n_1\: n_2 \: .... \: n_r\end{matrix}\right)=\dfrac{n!}{n_1!n_2!...n_r!}

with k!=k×(k1)×(k2)×....×1k!=k\times (k-1)\times (k-2)\times ....\times 1.

We know that five players are each dealt 5 of the 52 cards, the number of cards remaining are then:

n6=nn1n2n3n4n5=5255555=27n_6=n-n_1-n_2-n_3-n_4-n_5=52-5-5-5-5-5=27

Using the definition of multinomial coefficients, we then obtain:

(525555527)=52!5!5!5!5!5!27!=297,686,658,367,751,290,178,415,114,240\left(\begin{matrix}52 \\ 5\: 5 \: 5\: 5\: 5 \: 27\end{matrix}\right)=\dfrac{52!}{5!5!5!5!5!27!}=297,686,658,367,751,290,178,415,114,240

Thus there are 297,686,658,367,751,290,178,415,114,240 possible ways to dealt the cards.

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