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Question

In a pulse power circuit, the voltage of a 10μ\muF capacitor is zero for t<0 and v=5(1e4000t)v=5(1-e^{-4000t}) V for t>0. Determine the capacitor current and the energy stored in the capacitor at t=0ms and t=10ms.

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Current trough a capacitor is equal to:

ic(t)=Ctvc(t)\begin{align*} i_c(t)&=C\dfrac{\partial}{\partial{t}}v_c(t) \end{align*}

Energy stored in the capacitor:

wc(t)=tvci dt=tvcCdvcdt dt=Ctvcdv=C2vc2v()v(t)\begin{align*} w_c(t)&=\int_{-\infty}^t{v_c\cdot i \ dt}\\ &=\int_{-\infty}^t{v_c\cdot C\dfrac{dv_c}{dt}\ dt}\\ &=C\int_{-\infty}^t{v_cdv}\\ &=\dfrac{C}{2}v_c^2\bigg\vert_{v(-\infty)}^{v(t)} \end{align*}

From the given voltage we can calculate current:

i=101065(1e4000t)=50106(e4000t)(4000)=0.2e4000t\begin{align*} i&=10\cdot 10^{-6}\cdot 5(1-e^{-4000t})'\\ &=50\cdot 10^{-6}(-e^{-4000t})(-4000)\\ &=0.2e^{-4000t} \end{align*}

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