Question

In a series string, why does the largest $R$ dissipate the most power?

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Power dissipated by a resistor can be calculated as:

$P=I^2\cdot R$

The dissipated power is in direct correlation to both the current and the resistance. In a series circuit, the current is the same everywhere, so that means, the larger the resistance, the more power is dissipated on it.

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