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In a survey, 1640 out of 2246 randomly selected adults in the United States said that they use cell phones while driving (based on data from Zogby International). When testing the claim that the proportion of adults who use cell phones while driving is equal to 75% the TI- 83/84 Plus calculator display on the top of the next page is obtained. Use the results from the display with a 0.050.05 significance level to test the stated claim.

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Determine the value of the test-statistic:

z=p^pp(1p)n=0.73018699910.750.75(10.75)22462.17z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}=\dfrac{0.7301869991-0.75}{\sqrt{\dfrac{0.75(1-0.75)}{2246}}}\approx -2.17

The P-value is the corresponding probability of obtaining this value or more extreme, found in table A-2:

P(Z<2.17 or Z>2.17)=2×P(Z<2.17)=2×0.0150=0.0300P(Z<-2.17\text{ or }Z>2.17)=2\times P(Z<-2.17)=2\times 0.0150=0.0300

If the P-value is smaller than the significance level, reject the null hypothesis:

P<0.05 Reject H0P<0.05\Rightarrow \text{ Reject } H_0

There is sufficient evidence to reject the claim that the proportion of adults who use cell phones while driving is equal to 75%.

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