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In a Young"s two-slit experinemt a pieve of glass with an index of refraction nn and a thickness LL is placed in front of the upper slit. (a) Describe qualitatively what happens to the interference pattern. (b) Derive an expression for the intensity II of the light at points on a screen as a function of n,Ln, L, and θ\theta. Here θ\theta is the usual angle measured from the center of the two slits. That is, determine the equation analogous to Eq. (35.14) but that also involves LL and nn for the glass plate. (c) From your result in part (b) derive an expression for the values of θ\theta that locate the maxima in the interference pattern [that is, derive an equation analogous to Eq.

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a)\textbf{a)} \ \ If we have value of oil thickness λ=380 nm\lambda = 380 \ \text{nm}, expression of light wavelenght λ\lambda is defined as:

λ=λon\begin{equation*} \lambda = \frac{\lambda_o}{n} \end{equation*}

Interference between rays reflected from two surfaces of a thin film will be for constructive reflection from thin film and half-cycle relative phase shift where we insert the expression that consists the wavelenght of light λo\lambda_o through the oil (n=1.45n=1.45):

2t=(m+12)λ  (m=0,1,2,...)2t=(m+12)λonλo=2tn(m+12)\begin{align*} &2 \cdot t = \left( m + \frac{1}{2} \right) \cdot \lambda \ \ (m=0, 1, 2, ...) \\ \\ &2 \cdot t = \left( m + \frac{1}{2} \right) \cdot \frac{\lambda_o}{n} \\ \\ &\lambda_o = \frac{2 \cdot t \cdot n}{\left( m + \frac{1}{2} \right)} \end{align*}

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