In an adiabatic compression, a gas's temperature (a) increases; (b) decreases; (c) remains the same; (d) cannot be determined from the information given.

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Quizlet Admin · Accepted Answer

Writing down the first law we get:
$$\begin{align*}
\Delta U & = W + Q
\end{align*}$$
Because this is an adiabatic process, $Q = 0$. Because the gas is compressed, the work is done on it, $W > 0$. Putting all this together we get:
$$\begin{align*}
    \Delta U & = W > 0
\end{align*}$$
Because the internal energy of an ideal gas is only a function of temperature, the temperature of the gas will increase.

In an adiabatic compression, a gas's temperature (a) increases; (b) decreases; (c) remains the same; (d) cannot be determined from the information given.

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