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Question

In Fig. 19–36, calculate the primary current, IPI_\text{P}, if RL1R_{\text{L}_1} opens.

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In this exercise, we need to find primary current.

  • VP=120VV_\mathrm{P}=120 \,\mathrm{V}, Primary voltage.
  • IS1=0AI_\mathrm{{S_1}}=0\, \mathrm A, current will well be zero RL1R_{L_1} is open.
  • RL2=24ΩR_\mathrm{L_2}=24 \,\mathrm{\Omega}, loaded resistance in the secondary 22.
  • NP=250{N_\mathrm{P}}=250, number of turns in the primary.
  • NS2=50{N_\mathrm{S_2}}=50, number of turns in the secondary 22.

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