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In Fig. 19–38, what turns ratio, NPNs\dfrac{\text{N}_\text{P}}{\text{N}_\text{s}}, is required to obtain a secondary voltage of a. 60 Vac60\text{ Vac}? b. 600 Vac600\text{ Vac}? c. 420 Vac420\text{ Vac}? d. 24 Vac24\text{ Vac}? e. 12.6 Vac12.6\text{ Vac}?

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In this exercise, we need to find the turns ratio.

  • VP=120VV_\mathrm{P}=120 \,\mathrm{V}, Primary voltage.

In part (a)

  • VS=60VV_\mathrm{S}=60 \,\mathrm{V}, Secondary voltage.

In part (b)

  • VS=600VV_\mathrm{S}=600 \,\mathrm{V}, Secondary voltage.

In part (c)

  • VS=420VV_\mathrm{S}=420 \,\mathrm{V}, Secondary voltage.

In part (d)

  • VS=24VV_\mathrm{S}=24 \,\mathrm{V}, Secondary voltage.

In part (e)

  • VS=12.6VV_\mathrm{S}=12.6 \,\mathrm{V}, Secondary voltage.

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