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# In Fig. 19–38, what turns ratio, $\dfrac{\text{N}_\text{P}}{\text{N}_\text{s}}$, is required to obtain a secondary voltage of a. $60\text{ Vac}$? b. $600\text{ Vac}$? c. $420\text{ Vac}$? d. $24\text{ Vac}$? e. $12.6\text{ Vac}$?

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In this exercise, we need to find the turns ratio.

• $V_\mathrm{P}=120 \,\mathrm{V}$, Primary voltage.

In part (a)

• $V_\mathrm{S}=60 \,\mathrm{V}$, Secondary voltage.

In part (b)

• $V_\mathrm{S}=600 \,\mathrm{V}$, Secondary voltage.

In part (c)

• $V_\mathrm{S}=420 \,\mathrm{V}$, Secondary voltage.

In part (d)

• $V_\mathrm{S}=24 \,\mathrm{V}$, Secondary voltage.

In part (e)

• $V_\mathrm{S}=12.6 \,\mathrm{V}$, Secondary voltage.

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