## Related questions with answers

Question

In Fig. we saw earlier, $C_1=6.00 \mu \mathrm{F}, C_2=3.00 \mu \mathrm{F}, C_3=$ $4.00 \mu \mathrm{F}$, and $C_4=8.00 \mu \mathrm{F}$. The capacitor network is connected to an applied potential difference $V_{a b}$. After the charges on the capacitors have reached their final values, the voltage across $\mathrm{C}_3$ is $40.0 \mathrm{~V}$. What are (c) the voltage $V_{a b}$ applied to the network?

Solution

VerifiedAnswered 7 months ago

Answered 7 months ago

Step 1

1 of 2(c) We want to find the applied voltage across $ab$. As the capacitances $C_{123}$ and $C_{4}$ are in series, therefore, the applied voltage will be the summation of both voltage

$V_{ab} = V_{4} + V_{123} = 30 \,\text{V} + 40.0 \,\text{V} =\boxed{ 70.0\,\text{V}}$

## Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## More related questions

1/4

1/7