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In lab you find that a 1 -kg rock suspended above water weighs 10 N10 \mathrm{~N}. When the rock is suspended beneath the surface of the water, the scale reads 8 N8 \mathrm{~N}. c. What is the scale reading when the rock is released and rests at the bottom of the container?

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We will consider that in this physical situation, the density of a liquid is given by the mass per unit volume

ρ=mV\begin{align*} \rho &= \dfrac{m}{V} \end{align*}

As we know that the buoyant force is given by the decrease in the scale which is given by the following relation:

Buoyant Force=WaboveWbellow\begin{align*} \text{Buoyant Force} &= W_{above} - W_{bellow} \\ \end{align*}

In order to evaluate the scale reading when the rock is resting at the bottom of the container, we use the following relation:

Scale reading=Wwater+Wrock\begin{align*} \text{Scale reading} &= W_{water} + W_{rock} \\ \end{align*}

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