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Question

# In lab you find that a 1 -kg rock suspended above water weighs $10 \mathrm{~N}$. When the rock is suspended beneath the surface of the water, the scale reads $8 \mathrm{~N}$.

Solution

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We will consider that in this physical situation, the density of a liquid is given by the mass per unit volume

\begin{align*} \rho &= \dfrac{m}{V} \end{align*}

As we know that the buoyant force is given by the decrease in the scale which is given by the following relation:

\begin{align*} \text{Buoyant Force} &= W_{above} - W_{bellow} \\ \end{align*}

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