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Question

In order to study the relationship between the amount of sleep a student gets and his or her school performance, a researcher collected data from 120 students. The two-way frequency table shows the number of students who passed and failed an exam and the number of students who got more or less than 6 hours of sleep the night before.

Passed exam | Failed exam | Total | |
---|---|---|---|

Less than 6 hours of sleep | 12 | 10 | 22 |

More than 6 hours of sleep | 90 | 8 | 98 |

Total | 102 | 18 | 120 |

To the nearest percent, give the probability that a student who failed the exam got less than 6 hours of sleep.

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 4Let $F$ bet the event that the student failed the exam. Let $L$ be the event that the student got 6 hours of sleep.

First, we determine the probability that the student failed the exam. Out of the 120 students, 18 failed the exam. Thus,

$P(F)=\dfrac{18}{120}$

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